Answer for Probability - Independent events

https://365datascience.com/dwqa-answer/answer-for-probability-independent-events/ -

Hey Astro, 

 

Thanks for reaching out!

In this case, you have to calculate the conditional and unconditional probabilities of each event in each answer to determine this. If they are equal, the events are independent, so you need to compare P(A|B) and P(A) for every pair of events.

Since P(Diamond) = 1/4 and P(Diamond | Ace) = 1/4, then the two events are independent. Additionally, we can make a double check and see that P(Ace) = 1/13 and P(Ace|Diamond) = 13.

Alternatively, P(Queen) = 1/13, but P(Queen|Jack) = 0 (since the card can’t be a Queen if we know it’s a Jack) and also P(Ace of Spades) = 1/52, but P(Ace of Spades | 4) = 0 and similarly, P(4) = 1/13 but P(4 | Ace of Spades) = 0.

 

Hope this clears things up!

Best,

365 Vik

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